Expect name to still be a string after disambiguation

Check that encode('ascii') doesn't make it zero-length, but don't
actually return the encoded form.
lethe/HEAD
Jan Petykiewicz 4 years ago
parent 794ebb6b37
commit ad6fa88e53

@ -119,7 +119,7 @@ def build(patterns: Union[Pattern, List[Pattern]],
# Now create a structure for each pattern, and add in any Boundary and SREF elements
for pat in patterns_by_id.values():
structure = gdsii.structure.Structure(name=pat.name)
structure = gdsii.structure.Structure(name=pat.name.encode('ASCII'))
lib.append(structure)
structure += _shapes_to_elements(pat.shapes)
@ -385,7 +385,7 @@ def _subpatterns_to_refs(subpatterns: List[SubPattern]
for subpat in subpatterns:
if subpat.pattern is None:
continue
encoded_name = subpat.pattern.name
encoded_name = subpat.pattern.name.encode('ASCII')
# Note: GDS mirrors first and rotates second
mirror_across_x, extra_angle = normalize_mirror(subpat.mirrored)
@ -514,5 +514,5 @@ def disambiguate_pattern_names(patterns: Sequence[Pattern],
if len(encoded_name) > max_name_length:
raise PatternError('Pattern name "{!r}" length > {} after encode,\n originally "{}"'.format(encoded_name, max_name_length, pat.name))
pat.name = encoded_name
pat.name = suffixed_name
used_names.append(suffixed_name)

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