BREAKING change shape identifers generated when flattening

nolock
Jan Petykiewicz 3 years ago
parent db4148a0ff
commit a5900f6ade

@ -546,35 +546,31 @@ class Pattern(LockableImpl, AnnotatableImpl, Mirrorable, metaclass=AutoSlots):
"""
Removes all subpatterns and adds equivalent shapes.
Shape identifiers are changed to represent their original position in the
Shape/label identifiers are changed to represent their original position in the
pattern hierarchy:
`(L1_name (str), L1_index (int), L2_name, L2_index, ..., *original_shape_identifier)`
where
`L1_name` is the first-level subpattern's name (e.g. `self.subpatterns[0].pattern.name`),
`L2_name` is the next-level subpattern's name (e.g.
`self.subpatterns[0].pattern.subpatterns[0].pattern.name`) and
`L1_index` is an integer used to differentiate between multiple instance ofi the same
(or same-named) subpatterns.
`(L1_sp_index (int), L2_sp_index (int), ..., sh_index (int), *original_shape_identifier)`
where the original shape can be accessed as e.g.
`self.subpatterns[L1_sp_index].pattern.subpatterns[L2_sp_index].shapes[L1_sh_index]`
Returns:
self
"""
subpatterns = copy.deepcopy(self.subpatterns)
self.subpatterns = []
shape_counts: Dict[Tuple, int] = {}
for subpat in subpatterns:
# Update identifiers so each shape has a unique one
for ss, shape in enumerate(self.shapes):
shape.identifier = (ss,) + shape.identifier
for ll, label in enumerate(self.labels):
label.identifier = (ll,) + label.identifier
for pp, subpat in enumerate(subpatterns):
if subpat.pattern is None:
continue
subpat.pattern.flatten()
p = subpat.as_pattern()
# Update identifiers so each shape has a unique one
for shape in p.shapes:
combined_identifier = (subpat.pattern.name,) + shape.identifier
shape_count = shape_counts.get(combined_identifier, 0)
shape.identifier = (subpat.pattern.name, shape_count) + shape.identifier
shape_counts[combined_identifier] = shape_count + 1
for item in chain(p.shapes, p.labels):
item.identifier += (pp,) + item.identifier
self.append(p)
return self

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