add utils.vertices.poly_contains_points

nolock
Jan Petykiewicz 2 years ago committed by jan
parent fd0b2ba4cd
commit 97db83a1d5

@ -7,7 +7,9 @@ from .array import is_scalar
from .autoslots import AutoSlots
from .bitwise import get_bit, set_bit
from .vertices import remove_duplicate_vertices, remove_colinear_vertices
from .vertices import (
remove_duplicate_vertices, remove_colinear_vertices, poly_contains_points
)
from .transform import rotation_matrix_2d, normalize_mirror
#from . import pack2d

@ -52,3 +52,66 @@ def remove_colinear_vertices(vertices: ArrayLike, closed_path: bool = True) -> N
slopes_equal[[0, -1]] = False
return vertices[~slopes_equal]
def poly_contains_points(
vertices: ArrayLike,
points: ArrayLike,
include_boundary: bool = True,
) -> NDArray[numpy.int_]:
"""
Tests whether the provided points are inside the implicitly closed polygon
described by the provided list of vertices.
Args:
vertices: Nx2 Arraylike of form [[x0, y0], [x1, y1], ...], describing an implicitly-
closed polygon. Note that this should include any offsets.
points: Nx2 ArrayLike of form [[x0, y0], [x1, y1], ...] containing the points to test.
include_boundary: True if points on the boundary should be count as inside the shape.
Default True.
Returns:
ndarray of booleans, [point0_is_in_shape, point1_is_in_shape, ...]
"""
points = numpy.array(points, copy=False)
vertices = numpy.array(vertices, copy=False)
if points.size == 0:
return numpy.zeros(0)
min_bounds = numpy.min(vertices, axis=0)[None, :]
max_bounds = numpy.max(vertices, axis=0)[None, :]
trivially_outside = ((points < min_bounds).any(axis=1)
| (points > max_bounds).any(axis=1))
nontrivial = ~trivially_outside
if trivially_outside.all():
inside = numpy.zeros_like(trivially_outside, dtype=bool)
return inside
ntpts = points[None, nontrivial, :] # nontrivial points, along axis 1 of ndarray
verts = vertices[:, :, None]
y0_le = verts[:, 1] <= ntpts[..., 1] # (axis 0) y_vertex <= y_point (axis 1)
y1_le = numpy.roll(y0_le, -1, axis=0) # rolled by 1 vertex
upward = y0_le & ~y1_le
downward = ~y0_le & y1_le
dv = numpy.roll(verts, -1, axis=0) - verts
is_left = (dv[:, 0] * (ntpts[..., 1] - verts[:, 1]) # >0 if left of dv, <0 if right, 0 if on the line
- dv[:, 1] * (ntpts[..., 0] - verts[:, 0]))
winding_number = ((upward & (is_left > 0)).sum(axis=0)
- (downward & (is_left < 0)).sum(axis=0))
nontrivial_inside = winding_number != 0 # filter nontrivial points based on winding number
if include_boundary:
nontrivial_inside[(is_left == 0).any(axis=0)] = True # check if point lies on any edge
inside = nontrivial.copy()
inside[nontrivial] = nontrivial_inside
return inside

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