path() should return a tree

master
jan 7 months ago
parent 5001664547
commit 80e0c5daa8

@ -324,10 +324,10 @@ class Pather(Builder):
tool = self.tools.get(portspec, self.tools[None])
in_ptype = self.pattern[portspec].ptype
pat = tool.path(ccw, length, in_ptype=in_ptype, port_names=tool_port_names, **kwargs)
tree = tool.path(ccw, length, in_ptype=in_ptype, port_names=tool_port_names, **kwargs)
name = self.library.get_name(base_name)
self.library[name] = pat
return self.plug(Abstract(name, pat.ports), {portspec: tool_port_names[0]})
abstract = self.library << tree.rename_top(name)
return self.plug(abstract, {portspec: tool_port_names[0]})
def path_to(
self,

@ -65,7 +65,7 @@ class Tool:
out_ptype: str | None = None,
port_names: tuple[str, str] = ('A', 'B'),
**kwargs,
) -> Pattern:
) -> Library:
"""
Create a wire or waveguide that travels exactly `length` distance along the axis
of its input port.
@ -246,7 +246,7 @@ class BasicTool(Tool, metaclass=ABCMeta):
out_ptype: str | None = None,
port_names: tuple[str, str] = ('A', 'B'),
**kwargs,
) -> Pattern:
) -> Library:
_out_port, data = self.planL(
ccw,
length,
@ -270,7 +270,7 @@ class BasicTool(Tool, metaclass=ABCMeta):
opat, oport_theirs, oport_ours = data.out_transition
bb.plug(opat, {port_names[1]: oport_ours})
return bb.pattern
return tree
def planL(
self,
@ -422,7 +422,7 @@ class PathTool(Tool, metaclass=ABCMeta):
out_ptype: str | None = None,
port_names: tuple[str, str] = ('A', 'B'),
**kwargs,
) -> Pattern:
) -> Library:
out_port, dxy = self.planL(
ccw,
length,
@ -430,7 +430,7 @@ class PathTool(Tool, metaclass=ABCMeta):
out_ptype=out_ptype,
)
pat = Pattern()
tree, pat = Library.mktree('_path')
pat.path(layer=self.layer, width=self.width, vertices=[(0, 0), (length, 0)])
if ccw is None:
@ -445,7 +445,7 @@ class PathTool(Tool, metaclass=ABCMeta):
port_names[1]: Port(dxy, rotation=out_rot, ptype=self.ptype),
}
return pat
return tree
def planL(
self,

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