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poynting calculation comparison

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Jan Petykiewicz 2019-09-27 20:48:03 -07:00
parent 6333dbd110
commit 6850fe532f
1 changed files with 10 additions and 7 deletions
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17
examples/fdfd.py
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@ -62,6 +62,7 @@ def test0(solver=generic_solver):
J = [numpy.zeros_like(grid.grids[0], dtype=complex) for _ in range(3)]
J[1][15, grid.shape[1]//2, grid.shape[2]//2] = 1
'''
Solve!
'''
@ -195,16 +196,18 @@ def test1(solver=generic_solver):
H = functional.e2h(omega, dxes)(E)
poynting = 0.5 * fdtd.poynting(e=E, h=H.conj()) * dx * dx
cross1 = operators.poynting_e_cross(vec(E), dxes) @ vec(H).conj()
# cross2 = operators.poynting_h_cross(h.conj(), dxes) @ e
cross2 = operators.poynting_h_cross(vec(H), dxes) @ vec(E).conj() * -1
s1 = unvec(0.5 * numpy.real(cross1), grid.shape)
# s2 = unvec(0.5 * numpy.real(-cross2), grid.shape)
s2 = poynting.real
s2 = unvec(0.5 * numpy.real(cross2), grid.shape)
s0 = poynting.real
# s2 = poynting.imag
return s1, s2
return s0, s1, s2
s1x, s2x = poyntings(E)
pyplot.plot(s1x[0].sum(axis=2).sum(axis=1))
pyplot.plot(s2x[0].sum(axis=2).sum(axis=1))
s0x, s1x, s2x = poyntings(E)
pyplot.plot(s0x[0].sum(axis=2).sum(axis=1), label='s0')
pyplot.plot(s1x[0].sum(axis=2).sum(axis=1), label='s1')
pyplot.plot(s2x[0].sum(axis=2).sum(axis=1), label='s2')
pyplot.legend()
pyplot.show()
q = []