Poynting vector doc updates
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@ -288,9 +288,9 @@ If we discretize both space (m,n,p) and time (l), Maxwell's equations become
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$$ \\begin{align*}
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$$ \\begin{align*}
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\\tilde{\\nabla} \\times \\tilde{E}_{l,\\vec{r}} &= -\\tilde{\\partial}_t \\hat{B}_{l-\\frac{1}{2}, \\vec{r} + \\frac{1}{2}}
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\\tilde{\\nabla} \\times \\tilde{E}_{l,\\vec{r}} &= -\\tilde{\\partial}_t \\hat{B}_{l-\\frac{1}{2}, \\vec{r} + \\frac{1}{2}}
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+ \\hat{M}_{l-1, \\vec{r} + \\frac{1}{2}} \\\\
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- \\hat{M}_{l, \\vec{r} + \\frac{1}{2}} \\\\
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\\hat{\\nabla} \\times \\hat{H}_{l,\\vec{r} + \\frac{1}{2}} &= \\hat{\\partial}_t \\tilde{D}_{l, \\vec{r}}
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\\hat{\\nabla} \\times \\hat{H}_{l-\\frac{1}{2},\\vec{r} + \\frac{1}{2}} &= \\hat{\\partial}_t \\tilde{D}_{l, \\vec{r}}
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+ \\tilde{J}_{l-\\frac{1}{2},\\vec{r}} \\\\
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+ \\tilde{J}_{l-\\frac{1}{2},\\vec{r}} \\\\
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\\tilde{\\nabla} \\cdot \\hat{B}_{l-\\frac{1}{2}, \\vec{r} + \\frac{1}{2}} &= 0 \\\\
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\\tilde{\\nabla} \\cdot \\hat{B}_{l-\\frac{1}{2}, \\vec{r} + \\frac{1}{2}} &= 0 \\\\
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\\hat{\\nabla} \\cdot \\tilde{D}_{l,\\vec{r}} &= \\rho_{l,\\vec{r}}
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\\hat{\\nabla} \\cdot \\tilde{D}_{l,\\vec{r}} &= \\rho_{l,\\vec{r}}
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\\end{align*} $$
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\\end{align*} $$
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@ -311,9 +311,9 @@ and \\( \\epsilon \\) and \\( \\mu \\) are the dielectric permittivity and magne
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The above is Yee's algorithm, written in a form analogous to Maxwell's equations.
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The above is Yee's algorithm, written in a form analogous to Maxwell's equations.
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The time derivatives can be expanded to form the update equations:
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The time derivatives can be expanded to form the update equations:
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[code: Maxwell's equations]
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[code: Maxwell's equations updates]
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H[i, j, k] -= (curl_forward(E[t])[i, j, k] - M[t, i, j, k]) / mu[i, j, k]
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H[i, j, k] -= dt * (curl_forward(E)[i, j, k] + M[t, i, j, k]) / mu[i, j, k]
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E[i, j, k] += (curl_back( H[t])[i, j, k] + J[t, i, j, k]) / epsilon[i, j, k]
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E[i, j, k] += dt * (curl_back( H)[i, j, k] + J[t, i, j, k]) / epsilon[i, j, k]
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Note that the E-field fore-vector and H-field back-vector are offset by a half-cell, resulting
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Note that the E-field fore-vector and H-field back-vector are offset by a half-cell, resulting
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in distinct locations for all six E- and H-field components:
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in distinct locations for all six E- and H-field components:
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@ -383,7 +383,7 @@ $$
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\\begin{align*}
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\\begin{align*}
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\\tilde{\\nabla} \\times \\tilde{E}_{l,\\vec{r}} &=
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\\tilde{\\nabla} \\times \\tilde{E}_{l,\\vec{r}} &=
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-\\tilde{\\partial}_t \\hat{B}_{l-\\frac{1}{2}, \\vec{r} + \\frac{1}{2}}
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-\\tilde{\\partial}_t \\hat{B}_{l-\\frac{1}{2}, \\vec{r} + \\frac{1}{2}}
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+ \\hat{M}_{l-1, \\vec{r} + \\frac{1}{2}} \\\\
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- \\hat{M}_{l-1, \\vec{r} + \\frac{1}{2}} \\\\
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\\mu^{-1}_{\\vec{r} + \\frac{1}{2}} \\cdot \\tilde{\\nabla} \\times \\tilde{E}_{l,\\vec{r}} &=
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\\mu^{-1}_{\\vec{r} + \\frac{1}{2}} \\cdot \\tilde{\\nabla} \\times \\tilde{E}_{l,\\vec{r}} &=
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-\\tilde{\\partial}_t \\hat{H}_{l-\\frac{1}{2}, \\vec{r} + \\frac{1}{2}} \\\\
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-\\tilde{\\partial}_t \\hat{H}_{l-\\frac{1}{2}, \\vec{r} + \\frac{1}{2}} \\\\
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\\hat{\\nabla} \\times (\\mu^{-1}_{\\vec{r} + \\frac{1}{2}} \\cdot \\tilde{\\nabla} \\times \\tilde{E}_{l,\\vec{r}}) &=
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\\hat{\\nabla} \\times (\\mu^{-1}_{\\vec{r} + \\frac{1}{2}} \\cdot \\tilde{\\nabla} \\times \\tilde{E}_{l,\\vec{r}}) &=
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@ -488,11 +488,16 @@ $$
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K_x^2 + K_y^2 + K_z^2 = \\Omega^2 \\mu \\epsilon = \\Omega^2 / c^2
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K_x^2 + K_y^2 + K_z^2 = \\Omega^2 \\mu \\epsilon = \\Omega^2 / c^2
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$$
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$$
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where \\( c = \\sqrt{\\mu \\epsilon} \\).
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Assuming real \\( (k_x, k_y, k_z), \\omega \\) will be real only if
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Assuming real \\( (k_x, k_y, k_z), \\omega \\) will be real only if
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$$ c^2 \\Delta_t^2 = \\frac{\\Delta_t^2}{\\mu \\epsilon} < 1/(\\frac{1}{\\Delta_x^2} + \\frac{1}{\\Delta_y^2} + \\frac{1}{\\Delta_z^2}) $$
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$$ c^2 \\Delta_t^2 = \\frac{\\Delta_t^2}{\\mu \\epsilon} < 1/(\\frac{1}{\\Delta_x^2} + \\frac{1}{\\Delta_y^2} + \\frac{1}{\\Delta_z^2}) $$
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If \\( \\Delta_x = \\Delta_y = \\Delta_z \\), this simplifies to \\( c \\Delta_t < \\frac{\\Delta_x}{\\sqrt{3}} \\).
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If \\( \\Delta_x = \\Delta_y = \\Delta_z \\), this simplifies to \\( c \\Delta_t < \\Delta_x / \\sqrt{3} \\).
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This last form can be interpreted as enforcing causality; the distance that light
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travels in one timestep (i.e., \\( c \\Delta_t \\)) must be less than the diagonal
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of the smallest cell ( \\( \\Delta_x / \\sqrt{3} \\) when on a uniform cubic grid).
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Grid description
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Grid description
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@ -1,6 +1,9 @@
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"""
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"""
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Utilities for running finite-difference time-domain (FDTD) simulations
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Utilities for running finite-difference time-domain (FDTD) simulations
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See the discussion of `Maxwell's Equations` in `meanas.fdmath` for basic
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mathematical background.
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Timestep
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Timestep
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========
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========
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@ -19,13 +22,120 @@ Based on this, we can set
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The `dx_min`, `dy_min`, `dz_min` should be the minimum value across both the base and derived grids.
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The `dx_min`, `dy_min`, `dz_min` should be the minimum value across both the base and derived grids.
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Poynting Vector
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Poynting Vector and Energy Conservation
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===============
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=======================================
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# TODO
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Let
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$$ \\begin{align*}
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\\tilde{S}_{l, l', \\vec{r}} &=& &\\tilde{E}_{l, \\vec{r}} \\otimes \\hat{H}_{l', \\vec{r} + \\frac{1}{2}} \\\\
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&=& &\\vec{x} (\\tilde{E}^y_{l,m+1,n,p} \\hat{H}^z_{l',\\vec{r} + \\frac{1}{2}} - \\tilde{E}^z_{l,m+1,n,p} \\hat{H}^y_{l', \\vec{r} + \\frac{1}{2}}) \\\\
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& &+ &\\vec{y} (\\tilde{E}^z_{l,m,n+1,p} \\hat{H}^x_{l',\\vec{r} + \\frac{1}{2}} - \\tilde{E}^x_{l,m,n+1,p} \\hat{H}^z_{l', \\vec{r} + \\frac{1}{2}}) \\\\
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& &+ &\\vec{z} (\\tilde{E}^x_{l,m,n,p+1} \\hat{H}^y_{l',\\vec{r} + \\frac{1}{2}} - \\tilde{E}^y_{l,m,n,p+1} \\hat{H}^z_{l', \\vec{r} + \\frac{1}{2}})
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\\end{align*}
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$$
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where \\( \\vec{r} = (m, n, p) \\) and \\( \\otimes \\) is a modified cross product
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in which the \\( \\tilde{E} \\) terms are shifted as indicated.
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By taking the divergence and rearranging terms, we can show that
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$$
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\\begin{align*}
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\\hat{\\nabla} \\cdot \\tilde{S}_{l, l', \\vec{r}}
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&= \\hat{\\nabla} \\cdot (\\tilde{E}_{l, \\vec{r}} \\otimes \\hat{H}_{l', \\vec{r} + \\frac{1}{2}}) \\\\
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&= \\hat{H}_{l', \\vec{r} + \\frac{1}{2}} \\cdot \\tilde{\\nabla} \\times \\tilde{E}_{l, \\vec{r}} -
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\\tilde{E}_{l, \\vec{r}} \\cdot \\hat{\\nabla} \\times \\hat{H}_{l', \\vec{r} + \\frac{1}{2}} \\\\
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&= \\hat{H}_{l', \\vec{r} + \\frac{1}{2}} \\cdot
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(-\\tilde{\\partial}_t \\mu_{\\vec{r} + \\frac{1}{2}} \\hat{H}_{l - \\frac{1}{2}, \\vec{r} + \\frac{1}{2}} -
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\\hat{M}_{l-1, \\vec{r} + \\frac{1}{2}}) -
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\\tilde{E}_{l, \\vec{r}} \\cdot (\\hat{\\partial}_t \\tilde{\\epsilon}_\\vec{r} \\tilde{E}_{l'+\\frac{1}{2}, \\vec{r}} +
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\\tilde{J}_{l', \\vec{r}}) \\\\
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&= \\hat{H}_{l'} \\cdot (-\\mu / \\Delta_t)(\\hat{H}_{l + \\frac{1}{2}} - \\hat{H}_{l - \\frac{1}{2}}) -
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\\tilde{E}_l \\cdot (\\epsilon / \\Delta_t )(\\tilde{E}_{l'+\\frac{1}{2}} - \\tilde{E}_{l'-\\frac{1}{2}})
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- \\hat{H}_{l'} \\cdot \\hat{M}_{l-1} - \\tilde{E}_l \\cdot \\tilde{J}_{l'} \\\\
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\\end{align*}
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$$
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where in the last line the spatial subscripts have been dropped to emphasize
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the time subscripts \\( l, l' \\), i.e.
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$$
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\\begin{align*}
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\\tilde{E}_l &= \\tilde{E}_{l, \\vec{r}} \\\\
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\\hat{H}_l &= \\tilde{H}_{l, \\vec{r} + \\frac{1}{2}} \\\\
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\\tilde{\\epsilon} &= \\tilde{\\epsilon}_\\vec{r} \\\\
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\\end{align*}
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$$
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etc.
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For \\( l' = l + \\frac{1}{2} \\) we get
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$$
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\\begin{align*}
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\\hat{\\nabla} \\cdot \\tilde{S}_{l, l + \\frac{1}{2}}
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&= \\hat{H}_{l + \\frac{1}{2}} \\cdot
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(-\\mu / \\Delta_t)(\\hat{H}_{l + \\frac{1}{2}} - \\hat{H}_{l - \\frac{1}{2}}) -
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\\tilde{E}_l \\cdot (\\epsilon / \\Delta_t)(\\tilde{E}_{l+1} - \\tilde{E}_l)
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- \\hat{H}_{l'} \\cdot \\hat{M}_l - \\tilde{E}_l \\cdot \\tilde{J}_{l + \\frac{1}{2}} \\\\
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&= (-\\mu / \\Delta_t)(\\hat{H}^2_{l + \\frac{1}{2}} - \\hat{H}_{l + \\frac{1}{2}} \\cdot \\hat{H}_{l - \\frac{1}{2}}) -
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(\\epsilon / \\Delta_t)(\\tilde{E}_{l+1} \\cdot \\tilde{E}_l - \\tilde{E}^2_l)
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- \\hat{H}_{l'} \\cdot \\hat{M}_l - \\tilde{E}_l \\cdot \\tilde{J}_{l + \\frac{1}{2}} \\\\
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&= -(\\mu \\hat{H}^2_{l + \\frac{1}{2}}
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+\\epsilon \\tilde{E}_{l+1} \\cdot \\tilde{E}_l) / \\Delta_t \\ \\
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+(\\mu \\hat{H}_{l + \\frac{1}{2}} \\cdot \\hat{H}_{l - \\frac{1}{2}}
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+\\epsilon \\tilde{E}^2_l) / \\Delta_t \\ \\
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- \\hat{H}_{l+\\frac{1}{2}} \\cdot \\hat{M}_l \\ \\
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- \\tilde{E}_l \\cdot \\tilde{J}_{l+\\frac{1}{2}} \\\\
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\\end{align*}
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$$
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and for \\( l' = l - \\frac{1}{2} \\),
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$$
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\\begin{align*}
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\\hat{\\nabla} \\cdot \\tilde{S}_{l, l - \\frac{1}{2}}
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&= (\\mu \\hat{H}^2_{l - \\frac{1}{2}}
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+\\epsilon \\tilde{E}_{l-1} \\cdot \\tilde{E}_l) / \\Delta_t \\ \\
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-(\\mu \\hat{H}_{l + \\frac{1}{2}} \\cdot \\hat{H}_{l - \\frac{1}{2}}
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+\\epsilon \\tilde{E}^2_l) / \\Delta_t \\ \\
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- \\hat{H}_{l-\\frac{1}{2}} \\cdot \\hat{M}_l \\ \\
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- \\tilde{E}_l \\cdot \\tilde{J}_{l-\\frac{1}{2}} \\\\
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\\end{align*}
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$$
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These two results form the discrete time-domain analogue to Poynting's theorem.
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They hint at the expressions for the energy, which can be calculated at the same
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time-index as either the E or H field:
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$$
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\\begin{align*}
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U_l &= \\epsilon \\tilde{E}^2_l + \\mu \\hat{H}_{l + \\frac{1}{2}} \\cdot \\hat{H}_{l - \\frac{1}{2}} \\\\
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U_{l + \\frac{1}{2}} &= \\epsilon \\tilde{E}_l \\cdot \\tilde{E}_{l + 1} + \\mu \\hat{H}^2_{l + \\frac{1}{2}} \\\\
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\\end{align*}
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$$
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Rewriting the Poynting theorem in terms of the energy expressions,
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$$
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\\begin{align*}
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(U_{l+\\frac{1}{2}} - U_l) / \\Delta_t
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&= -\\hat{\\nabla} \\cdot \\tilde{S}_{l, l + \\frac{1}{2}} \\ \\
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- \\hat{H}_{l+\\frac{1}{2}} \\cdot \\hat{M}_l \\ \\
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- \\tilde{E}_l \\cdot \\tilde{J}_{l+\\frac{1}{2}} \\\\
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(U_l - U_{l-\\frac{1}{2}}) / \\Delta_t
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&= -\\hat{\\nabla} \\cdot \\tilde{S}_{l, l - \\frac{1}{2}} \\ \\
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- \\hat{H}_{l-\\frac{1}{2}} \\cdot \\hat{M}_l \\ \\
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- \\tilde{E}_l \\cdot \\tilde{J}_{l-\\frac{1}{2}} \\\\
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\\end{align*}
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$$
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This result is exact an should practically hold to within numerical precision. No time-
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or spatial-averaging is necessary.
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Note that each value of \\( J \\) contributes to the energy twice (i.e. once per field update)
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despite only causing the value of \\( E \\) to change once (same for \\( M \\) and \\( H \\)).
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Energy conservation
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===================
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# TODO
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Boundary conditions
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Boundary conditions
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===================
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===================
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@ -73,9 +73,9 @@ def maxwell_h(dt: float, dxes: dx_lists_t = None) -> fdfield_updater_t:
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The full update should be
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The full update should be
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H -= (curl_forward(E[t]) - M) / mu
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H -= (curl_forward(E[t]) + M) / mu
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which requires an additional step of `H += M / mu` which is not performed
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which requires an additional step of `H -= M / mu` which is not performed
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by the generated function; this step can be omitted if there is no magnetic
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by the generated function; this step can be omitted if there is no magnetic
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current `M`.
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current `M`.
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